Write an algorithm, in the form of a C-Language?
- divides two float variables
- finds the remainder by using explicit casting.
Solution
#include <stdio.h>
int main()
{
float a,b;
int c;
a=10.3;
b=5.2;
c=(int)a%(int)b;
printf("Result is %d",c);
return 0;
}
